Subject : A load calc problem


From: pjm@nando.net (paul milligan)

Here's one I just got through working on....

This is a WEIRD system. 100 % roof-top air is sucked into a water-based air scrubber ( we haven't got to the fan yet, so the pressure here is negative ). There is a pre-filter ( 90% pleat ) and steam pre-heat coil ( for winter only, not in effect right now ), both of which I'll ignore. :~)

After the water-scrubber, the air is sucked into the fan, and then expelled into ~ 10 running linear feet of solid charcoal, HEPA, and other bio-active mixed-media filtration, in an 18" x 18 " plenum. Gross static pressure reaches 18" water column due to restriction of water-scrubber and filtration, but I'll ignore that, as final WC is ~ 1", therefore I take all heat of compression / expansion to be a net wash for my purposes when I then get to the heat/cool segments at a still-strong but normal static.

After the above, there is a 2 ton R22 AC unit to 'pre-cool' the roof air. There is then a 5 ton Carrier R22 residential scroll AC, and then a 4KW electric element.

Final target of the system is 70 F air at 50 % - 60 % RH, year round, at 500 CFM. Yes, I said 500 CFM.

I just got through tuning and repairing the system such that it holds 70 F +/- 0.5, and 55 % RH +/- 5 %. I hope to get that RH a little tighter next week, tweaking the Faircloth multiplier down just a bit.

Controls are as follows, in equipment sequence : Steam pre-heat is on a Penn OA stat for winter pre-heat only. Scrubber sump temp is whatever evaporation and OA and makeup temp drive it to, no control.

2 ton unit runs continuous, no control.

5 ton unit has a variable hot gas bypass, which is controlled by pneumatics, which sense RH only. RH sensor ( standard 3 - 15 lb) goes to a Barber-Coleman prop-band controller, then to a Faircloth variable multiplier, with final pneumatic output on the HG bypass being 0-80 lbs pneumatic control pressure, and minimum HG bypass pressure set at ~ 60 lbs suction to the 5 ton unit, to prevent ice. TXV is set to provide minimum compressor cooling when in maximum bypass ( Andy, you're just gonna have to let me slide on this one :~) ).

Electric reheat is under DDC PID control, for sensible heat only ( thermistor input ). There is interconection between the controls of any one piece of equipment to any other piece.

I corrected some initial problems with this 'rig', such as : The low-level pneumatics were being run at 35 lbs ( instead of 20 ). The high level pneumatics were being run at 120 lb ( instead of 80 ). The RH sensor was _BETWEEN_ the 5 ton coil and the reheat element, 6 inches from the evap coil, and routinely had liquid water dripping off it ( once the water falls , does it become 'low' humidity ? :~) ). The sensible thermistor was ~6 inches downstream from the reheat element ( I measured >20 F laminar stratification delta in this region ). After I regained consciousness, I moved both sensors 30' downstream. The 5 ton unit was running 300 lb head on a cool day, 400+ on a hot day. Unit would cut out on head and thermal regularly. Unit has had 3 compressors in 2 years ( whole system is two years old ). Sight glass NEVER came even close to clear with these pressures, and unit has NEVER had a clear sight glass in 2 years, from what I've been told. There is a solenoid in the liquid line, between the guage ports and the condensor. After I evacuated the system with this solenoid _OPEN_ ( which I don't think had ever been done ), the system now runs a clear glass with a 260 head on a hot summer day. Ah, yes, the glories of air ( or nitrogen ) in a system ! :~(

So anyway, on to my question...

My intuition told me that 5 ton was hugely oversized for 500 CFM load. Then I ran the numbers, and the numbers tell me that my intuition needs a long vacation. Would some kind ( engineering type ) soul care to comment on the numbers below, please ? This is a bit out of my usual area. Please remember that some of the below are approximations from my psychrometric chart, I just want to know if my understanding is somewhere in the ball park.

Clean air supply system - sample load

If setpoint = 70 F , 50 % RH

If input air = 85 F, 85 % RH

Volume is ~ 500 CFM at all times

Input = 85 F, 85 % RH = 50 btu / lb, @ 14.25 cu.ft. / lb = 105,623 BTU/HR

because :

1 / 14.25 cu. ft. / lb = .0701... lb / cu. ft.

0701 lb / cu. ft. x 500 CFM = 35 lb / minute

35 lb / minute x 50 BTU / lb = 1754 BTU / minute

1754 BTU / minute x 60 = 105,623 BTU / HR enthalpy of input air

MINUS

Ouput = 70 F, 50 % RH = 25 btu / lb, @ 13 .5 cu.ft. / lb = 55,555 BTU/HR

because :

1 / 13.5 cu. ft. / lb = .0740... lb / cu. ft.

0740 lb / cu. ft. x 500 CFM = 37 lb / minute

37 lb / minute x 25 BTU / lb = 925 BTU / minute

925 BTU / minute x 60 = 55,555 BTU / HR enthalpy of output air

PLUS :

Assume : 4 KW re-heat element runs at 50 % duty cycle to maintain sensible at 70 F, under PID control

Thus 4,000 W x 3.41 BTU / W = 13640 BTUH, x 50 % cycle = 6,820 BTU / HR

105,623 - 55,555 + 6,820 = 56,888 BTU / HR total enthalpic load

56,888 / 12,000 = 4.74 TON total combined sensible and latent load.

Therefor, 5 ton ( plus capacity from the prior 2 ton ) is rock and roll city.

I eagerly await the input of those who do this stuff for a living.

You'll have to excuse me now, I think I'm getting a headache. :~)

Paul


From: pjm@nando.net (paul milligan)

Oops...

I just realized a basic error I made by adding the reheat to total load. My actual proposed total load should be 4.17 ton, not 4.74.

Please continue to educate me from there. :~)

Paul


From: Dave Munro

I don't have my psych chart with me, and don't know what the altitude/ barometric pressure is for this discussion, so I will not address the math in this post as much as some of the basic questions and statements.

1. Allowances for fan heat need to be included. If the fan motor is in the air stream the motor heat must also be added. (The purpose of the 2 ton cooling coil may have been to counteract the fan heat???). It may be useful to verify the airflow and take entering and leaving air temperatures.

2. Unless there is active control of the air flow rate, the assumption that the system is flowing 500 cfm probably is not true. The actual air flow rate will be determined by the fan speed, the flow rate will vary depending on the inlet conditions (barometric pressure and air density).

3. Are we controlling the room or the supply air to the 70 F and 50-60% RH design criteria. What are the estimated minimum and maximum sensible and latent room heat gains?

Based on the results of tuning and repairs, it looks as though you have addressed most of the issues relative to cooling. There may be issues in the future related to the heating and/or intermittent weather conditions:

1. What are the steam coil control parameters?

2. Does the air scrubber run continuously (24 hours per day 365 days per year)? Do you know its saturation efficiency? Can you measure the entering dry bulb and wetbulb conditions as well as the leaving dry bulb?

3. Does the reheat coil have SCR control, or are their multiple stages?

Please excuse my ignorance - What is a Faircloth variable multiplier?

Dave Munro


From: pjm@nando.net (paul milligan)

In article
Dave Munro wrote:

~~>1. Allowances for fan heat need to be included. If the fan motor is in the air stream the motor heat must also be added.

Very true, but the fan motor is not in the airstream. I think I can ignore gain from bearing friction.

~~>2. Unless there is active control of the air flow rate, the assumption that the system is flowing 500 cfm probably is not true.

A good point I had missed. Very true. Also, the scientist types who use the test chambers fed by this system have balancing dampers under their control. 500 is the design spec for max load. I really have no idea how close to that they run, so I take that as my max load.

~~>3. Are we controlling the room or the supply air to the 70 F and 50-60% RH design criteria. What are the estimated minimum and maximum sensible and latent room heat gains?

Supply air at those numbers in the supply duct. There are no gains ( at least that I need to deal with ) in the test chambers, because this is a single pass, 100 % roof air system. BTW, it has a special evap for extra latent bias.

~~>Based on the results of tuning and repairs, it looks as though you have addressed most of the issues relative to cooling. There may be issues in the future related to the heating and/or intermittent weather conditions:

Yeh, she barcharts for a 5 day period now at +/- 0.5 F, +/- 5%, each centered on set point. Acceptable to the scientists using the chambers, so I can live with it.

> What are the steam coil control parameters?

Don't know, it's for winter anti-freeze pre-heat only, so I haven't looked at it yet. Roughly, I think it maintains a minimum 45F intake air.

>2. Does the air scrubber run continuously (24 hours per day 365 days per year)? Do

Yes

>you know its saturation efficiency?

NO, and a major question in my mind. I can only SWAG it at 85 -95 %

>Can you measure the entering dry bulb and wetbulb conditions as well as the leaving dry bulb?

Around the system, yes, but not around the scrubber by itself.

~~>3. Does the reheat coil have SCR control, or are their multiple stages?

Yes, SCR on a PID controller. That seems to work very well. The problem is no interaction between it and the RH control. Each one just tries to do it's own thing, regardless of the other.

~~>Please excuse my ignorance - What is a Faircloth variable multiplier?

Your ignorance is vastly exceeded by my own. :~) The Faircloth is a pneumatic device that multiplies it's control input by a set amount. I think ( not sure ) this is also called a ratio relay by some other brands.

The difficult thing in the RH control is that the sensor is 3-15, then the Barber-Coleman is 0-20 output into the Faircloth, wich takes that 0 -20 and multiplies it proportionaly ( as a throttling range kind of thing ) to become 0 - 80 lbs output to the control head of the HG bypass.

This whole rig series is REAL sensitive, and oscillates a bit no matter what I do.

Given this system being a 'gross enthalpy' kind of thing, with no 'room' loads and no recirculation of any air, does that help look at the loads ?

Thanks, Dave, for looking at this one ! :~)

Paul


From: Dave Munro

Theory and normal design practice is to add fan heat for 'compressing' the air, plus the motor heat if the motor is in the air stream. The fan heat, not including motor heat can be estimated by the following formula:

Q=V*P/N/6356; Q=Fan heat, bhp

V=Air flow rate, scfm

P=Fan total pressure, inches W.C.

N=Fan efficiency

The fan efficiency is normally in the range of 50-75% for typical applications (this isn't a normal application).

Assuming 50% fan efficiency:

Q=500*18/.5/6356 bhp

Q=2.8 bhp * (2545 Btuh/bhp)

Q=7,200 Btuh

You may be able to find out the fan efficiency from the fan manufacturer. It would be easier to measure motor voltage and current, assume appropriate values for power factor and motor efficiency, and estimate the fan heat. >~~>2. Unless there is active control of the air flow rate, the assumption that the system is flowing 500 cfm probably is not true.

> A good point I had missed. Very true. Also, the scientist types who use the test chambers fed by this system have balancing dampers under their control. 500 is the design spec for max load. I really have no idea how close to that they run, so I take that as my max load.

Assuming that the air balancer is setting fan speed based on the room air conditions, and a need for precision, I would use the density of air at the room design conditions of 70 degrees and 55% RH (and what ever altitude the project is at) to determine the pounds of air, and use the same pounds of air per minute for each of the psychometric processes.

>3. Are we controlling the room or the supply air to the 70 F and 50-60% RH design criteria. What are the estimated minimum and maximum sensible and latent room heat gains?

> Supply air at those numbers in the supply duct. There are no gains ( at least that I need to deal with ) in the test chambers, because this is a single pass, 100 % roof air system. BTW, it has a special evap for extra latent bias.

Unless the bar chart recorder and temperature sensors used to control the cooling coil and reheat coil are in the duct, I would tend to think that we care controlling the room to 70 F and 55% RH.

>~~>1. What are the steam coil control parameters?

> Don't know, it's for winter anti-freeze pre-heat only, so I haven't looked at it yet. Roughly, I think it maintains a minimum 45F intake air.

The steam coil would need to heat the air up much hotter than 45 degrees in order for the air scrubber to add moisture. Depending on the outdoor design criteria for minimum air temperature and humidity and the saturation efficiency of the air scrubber, it may be necessary to heat the air to 95 F or more.

>2. Does the air scrubber run continuously (24 hours per day 365 days per year)? Do

> Yes

>~~>you know its saturation efficiency?

> NO, and a major question in my mind. I can only SWAG it at 85 -95 %

>~~>Can you measure the entering dry bulb and wetbulb conditions as well as the leaving dry bulb?

> Around the system, yes, but not around the scrubber by itself.

It may be appropriate in the future to measure outdoor dry bulb temperature and relative humidity, leaving dry bulb temperature, estimate the outdoor wet bulb and saturation efficiency. Let's differ this until later, if and when you need it.

>Paul


From: Kirk Wilson

Uh!...a picture of this one would be helpful. Here is a quick looksy.

When I do load calcs (it's been a while), I use the ASHRAE Load Calculation Manual or computer progams based on it. Your system has the following loads:

1. Outside air from 85/85% [45 BTU/Lb] to room condition 70/50% [25.5 BTU/Lb] Use BTU/hr = 4.5 (CFM) (Delta h) = 44,000 BTU/hr (3.7 tons) (Actually your washer saturates the air to 81/99%,constant wet bulb, but the enthalpy is about the same)

2. Fan Heat from Table 4, Page 26.10 of 1993 ASHRAE Fundamentals 2 HP motor (if this is size) = 6,440 BTU/Hr (motor in/ fan in)

3. Reheat Load, if it is a constant. [BTU/hr = 1.1 (CFM) (delta temp)]

3. Room Load - You've got to define these; lights, people, equipment, skin, etc.

Add all of these up for your cooling load. With your supply airflow fixed at 500 CFM, your sensible load will define your supply air temperature.

Your outside air load uses 3.7 tons of your 7 tons on a design day.

Hope this helps.


From: jjr@atlanta.com (Jim Riticher)

pjm@nando.net (paul milligan) wrote:
> Dave Munro wrote:

>~~>1. Allowances for fan heat need to be included. If the fan motor is in the air stream the motor heat must also be added.

> Very true, but the fan motor is not in the airstream. I think I can ignore gain from bearing friction.

This is a not-uncommon fallacy. You _CAN'T IGNORE_ the fan heat, especially at the static pressures discussed. It matters little where the fan -motor- is located. The fan -heat- will show up in the airstream no matter what.

Key point: A rotating fan wheel or pump impeller is pretty much the definition of "paddle wheel work" heating up a control volume, straight from Thermo 101. The fluid (air, water, salad dressing, you pick it) stream is heated by the wheel regardless of the location of motor.

The only effect of the motor location (in or out of the airstream) is where the heat created by motor inefficiency goes. If the motor is not in the air stream, the motor inefficiency heats up the room where the motor sits instread of the air stream. If this room is a return air plenum for an air handling unit (a common situation), this motor inefficiency heat becomes a "return air" load.

With some attempts at transmitting equations:

Motor kW = Fan kW / motor efficiency

-in shorthand-

kWm = kWf / nm

Motor in airstream = > Air stream heated at the rate of (kWm)

Motor out of airstream => Air stream heated at the rate of (kWf) Room where where motor sits heated at rate of (kWm-kWf), or [kWm X (1 - nm)]

All that said, I haven't tried to run your calcs out (my net connection is at home and all my texts and handbooks are at the office). However, I bet you can find the source of a lot of missing BTU's in the equation if you take the above to heart.

James J. Riticher, P.E. (Jim)
Environmental Design International
jjr@atlanta.com



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